Thanks, merlyn++.

Note that in the following cases, "last element" doesn't mean the same thing each time.

I'd actually change one entry:

Because it isn't the "last element" of the "list of scalar values that this operation would produce if called in a list context" but is instead the "last element" in the "list of Perl expressions that are separated by commas". Likewise, I might change the other two to "last scalar value" to be clearer.

This is another perfect example of why "list" doesn't just mean one thing when talking about Perl. Each of those cases return the "last element" of some "list", it is just that "list" means two different things in those two cases.

I think this is a big part of why people get confused and people argue when talking about "lists" in Perl. Since "list context", "scalar context", and "scalar" all have precise definitions in Perl, it is natural to think that "list" has a precise definition as well.

#!/usr/bin/perl -wl
use strict;

my @idx= ( 2, 99, 5 );
my @a2z= ( 'a'..'z' );
my @arr= ( 10..16 );

print        '(@arr,@a2z):       ',
      scalar( (@arr,@a2z) );
print        '(@arr,@a2z)[@idx]: ',
      scalar( (@arr,@a2z)[@idx] );
print        '@arr[@idx]:        ',
      scalar( @arr[@idx] );
[download]

produces

Useless use of private array in void context at scalar.pl line 9.
(@arr,@a2z):       26
(@arr,@a2z)[@idx]: 15
@arr[@idx]:        15
[download]

So only the first item is lazy (passing the scalar context inside such that a "list of scalar values on the stack" doesn't get generated just to be mostly thrown away).

I still believe that the other two "should" have been lazy (pass their scalar context into @idx) but instead the developers of Perl were lazy and just wrote code to generate the list of scalar values and simply pick the last one at the last minute. But since slices in scalar context are more "edge" or "corner" cases, being lazy with the design was probably the right choice. (:

So $s = (10,20,30) does contain "a list in scalar context". Either one has to admit that or one has to not say that $s gets set the the "last element of the list". :)