Re: Sorting by the value of the inner hash

Sorry, I copy-paste the wrong subroutine

sub by_score {
 $totalscoreinv{$keyscore}{$b}<=>$totalscoreinv{$keyscore}{$a};
}
[download]

Comment on Re: Sorting by the value of the inner hash Download Code

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Re: Re: Sorting by the value of the inner hash by matija (Priest) on Mar 31, 2004 at 06:49 UTC
Well, without your either: Posting the whole relevant section of your new code or Telling us exactly how it's not working It's hard for any of us to help you.	[reply]
Re: Re: Re: Sorting by the value of the inner hash by Anonymous Monk on Mar 31, 2004 at 07:33 UTC
1. Modified code `$totalscoreinv{$key1}{key2}= $totalscore; foreach $keyscore (keys %totalscoreinv){ print OUT "\n\nFirst key:$keyscore\n"; foreach my $keyscore2 (sort by_score keys %{$totalscoreinv{$keyscore +}}){ printf(OUT "%30s %s\n", "$keyscore2= ", "$totalscoreinv{$keyscore} +{$keyscore2}"); } } sub by_score { $totalscoreinv{$keyscore}{$b}<=>$totalscoreinv{$keyscore}{$a}; }` [download] 2. well..as simple as it is not sorting at all. Here an excerpt of my results `First key:700200 ----------------------------------------------------------- 523261= -509.711586526694 523237= -494.393864137596 523246= -438.024029240629 523424= -521.488541326437 523247= -470.547762535975` [download] Thanks	[reply] [d/l] [select]
Re: Re: Re: Sorting by the value of the inner hash by Anonymous Monk on Mar 31, 2004 at 07:00 UTC
I moved it to the inner loop, and still it is not working. Thanks	[reply]