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( [id://3333]=superdoc: print w/replies, xml ) Need Help??

The "recurrence" function should return the "next" recurrence. This is one way to implement it:

#!/usr/bin/perl use strict; use warnings; use DateTime; use DateTime::Format::Strptime; use Datetime::Set; # use Data::Dumper; my $strp = DateTime::Format::Strptime->new( pattern => '%Y-%m-%d %T', ); my $datf = qq{2012-01-01 04:00:00}; my $datt = qq{2012-01-02 23:00:00}; my $start = $strp->parse_datetime($datf); my $end = $strp->parse_datetime($datt); my $iter; my $set = DateTime::Set->from_recurrence( after => $start, before => $end, recurrence => sub { return $_[0]->add( hours => 1 )->truncate( to => 'hour' ) }, ); print "first set:\n"; $iter = $set->iterator; while ( my $dt = $iter->next ) { print $dt->datetime, "\n"; }; my $set2 = $set->grep( sub { return ( $_->hour > 7 && $_->hour < 23); } ); print "second set:\n"; $iter = $set2->iterator; while ( my $dt = $iter->next ) { print $dt->datetime, "\n"; };

In reply to Re^5: A question to iterator in Datetime::Event::Recurrence by fglock
in thread A question to iterator in Datetime::Event::Recurrence by vagabonding electron

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