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Think about Loose Coupling

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This is another approach. Read the file names in the output directory, filter out the ones that aren't really simple files (maybe there is some directory with a similar name), get the revision numbers of those files, get the max revision number and then add one to that.

#!/usr/bin/perl -w use strict; use List::Util qw(max); # List::Util is a core module # that means you don't have to # install it - its already there. my $output_dir = 'C:/TEMP'; my $program_root_name = "some_prog"; opendir DIR, $output_dir or die "cannot open $output_dir for reading $!"; my @current_numbers = map { /^$program_root_name(\d+)$/ ? $1 : () } # just the numbers grep{ -f "$output_dir/$_"}readdir DIR; # only "real" files # not directories closedir DIR; # purely optional foreach (@current_numbers) #intermediate print routine... { print "$output_dir/$program_root_name$_ exists!\n"; } my $max_cur_number = max(@current_numbers); my $new_max = ++$max_cur_number; print "The next highest number is $new_max\n"; print "Full name of next file in sequence would be: ". "$output_dir/$program_root_name$new_max\n"; __END__ The above prints: Note: I made the dummy files: some_prog1 and some_prog3... C:/TEMP/some_prog1 exists! C:/TEMP/some_prog3 exists! The next highest number is 4 Full name of next file in sequence would be: C:/TEMP/some_prog4

In reply to Re: incrementing the file by Marshall
in thread incrementing the file by abcdefg

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