comment on

How would you do this:

sub foo { \('fred', 'bill') };;

print "${ foo() }";;
bill
[download]

if a scalar context was implied by "${ ... }"?

No. I can't think of a good use for it either :)

But given you have scalar to force a scalar context, but no list to do the opposite, the status quo gives the greatest flexibility. Whether there is a good use for that flexibility it was (still is) too early to judge :)

Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.

"Science is about questioning the status quo. Questioning authority".

In the absence of evidence, opinion is indistinguishable from prejudice.

"Too many [] have been sedated by an oppressive environment of political correctness and risk aversion."

In reply to Re: Why does foo() evaluate in array context in "${\foo()}"? by BrowserUk
in thread Why does foo() evaluate in array context in "${\foo()}"? by ELISHEVA

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