Hi,
Here in the for loop, the values passed is between 1 to 200000.
In the log file only 600 values are printed. How can I print all the values in the log file by creating 5 threads.
#! perl -slw
use strict;
use threads;
use threads::shared;
our $N ||= 100;
our $from=1;
our $to=200000;
sub worker {
my $tid = threads->tid;
my( $log, $semRef, $from, $to ) = @_;
for my $file ( $from .. $to ) {
## Simulate doing some processing
## Lock the log file semaphore before writing
lock $$semRef;
## And write to the log
printf $log "[%2d] Processesing file%3d\n",
$tid, $file;
## The lock is released automatically at the end of the block
}
}
## A shared variable used as a semaphore for the log file resource
my $logSem :shared;
## Open the log file in the main thread
open my $log, '>', 'myLog2' or die $!;
my @threads = map{
## create the workers passing the log file handle and semaphore
threads->create( \&worker, $log, \$logSem,$_*$N, $_*$N + $N -1);
} 0 .. 5; ## 5 threads each processing 100 "files"
## Wait till they are done
$_->join for @threads;
## close the log
close $log;
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