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No it isn't just some syntax - look at the starting hash in the OP - the problem revolves around the converting the original hash from a flattened linked list to a hash containing the equivalent linked list ... not just rewriting the hash definition..

FWIW, I've solved it thusly:

use warnings; use strict; use Data::Dumper; my $fll= { (4,-1), (2,6), (6,4), (3,5), (5,-1), (99,-1), }; my $ll = {}; sub doit { my $done = { %$fll }; while (%$done) { foreach (keys %$done) { my ($k,$v) = ($_, $done->{$_}); if ($v < 0) { %$ll = (%$ll, ($k, $v)); delete $done->{$k}; } else { if (exists $ll->{$v}) { $ll->{$k} = {$v => $ll->{$v}}; delete $done->{$k}; delete $ll->{$v}; } } } } } doit(); print Dumper $fll,$ll;
gives:
pointo1d@pointo1d-laptop:~$ perl tst.pl $VAR1 = { '6' => 4, '99' => -1, '4' => -1, '3' => 5, '2' => 6, '5' => -1 }; $VAR2 = { '99' => -1, '3' => { '5' => -1 }, '2' => { '6' => { '4' => -1 } } };
As, I think, required

Update:

Added my attempt at a solution.

A user level that continues to overstate my experience :-))

In reply to Re^3: How to get a ideal hash by Bloodnok
in thread How to get a ideal hash by pysome

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