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You appear to want to sort into conventional time order, but your date string will sort by day number, then by month and then by year -- which is backwards... Then you are sorting by seconds, then minutes and then hours -- also backwards. Or is that really what you want ?

The problem appears to be in two parts: (a) construct something that will sort into the order you want, (b) map that back to your actual keys. Perhaps:

use strict ; use warnings ; my %Date_Time = ( '03-12-2008' => { '0' => { '8' => { '5' => 'a', '15' => 'b', }, '08' => { '22' => 'c', '05' => 'd', }, }, }, '04-12-2008' => { '0' => { '5' => { '8' => 'e', }, }, }, '05-12-2008' => { '0' => { '5' => { '9' => 'f', }, }, }, ) ; my @order ; foreach my $date (keys %Date_Time) { my ($d, $m, $y) = split(/-/, $date) ; my $o = sprintf("%04d%02d%02d", $y, $m, $d) ; foreach my $sec (keys %{$Date_Time{$date}}) { foreach my $min (keys %{$Date_Time{$date}{$sec}}) { foreach my $hour (keys %{$Date_Time{$date}{$sec}{$min}}) { + push @order, $o . sprintf("%02d%02d%02d", $hour, $min, $sec) . ":$date:$hour:$min:$sec" ; } ; } ; } ; } ; @order = sort @order ; foreach my $o (@order) { my (undef, $date, $hour, $min, $sec) = split(/:/, $o) ; print "Date=>$date $hour:$min:$sec = ", $Date_Time{$date}{$sec}{$min +}{$hour}, "\n" ; } ;

In reply to Re: Sort Hash array using date by gone2015
in thread Sort Hash array using date by madtoperl

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