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$foo && $bar && print "something"; is equivalent to print "something" if $foo && $bar;. The last && is necessary in your code because only that makes the whole thing one expression.
-- Hofmator Code written by Hofmator and posted on PerlMonks is public domain. It is provided as is with no warranties, express or implied, of any kind. Posted code may not have been tested. Use of posted code is at your own risk. In reply to Re^4: asterisk use
by Hofmator
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