#!/usr/local/bin/perl
use strict;
use warnings;
%h=('1', 'one', '2', 'two', '3', 'three');
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Since you're under strict this won't even compile.

@arr=(1,2);
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Ditto! (But I won't insist further.)

foreach $key(keys %h)
{
push(@arr,$h{$key});
}
print @arr;
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Thus is correct.

foreach $key(keys %h)
{
push(@arr,$$h{$key});
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This is not. Why do you expect $h{$key} to be a scalar reference?

print "@arr\n";
}
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You probably want to print out of the loop. Be careful (also) when preparing test examples.

All in all I suspect (but it's hard to tell from your description of the problem) you be in a situation in which you have $href=\%h or the like, and then

push @arr, $href->{$key};
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