You're being bitten by precedence. Ternary ?: has a higher precedence than =, so what perl parses is:
Y:\tmp>perl -MO=Deparse,-p 470538.pl
(my(%hash) = ('A', 'on', 'B', 'on', 'C', 'off', 'D', 'off', 'E', 'off'
+));
foreach $_ (keys(%hash)) {
my($result);
(((exists($hash{$_}) && ($hash{$_} eq 'on')) ? ($result = 'OK') :
+$result) = 'KO');
print($result, "\n");
}
470538.pl syntax OK
You're effectively doing ($result='OK')='KO' in the case of a match, hence your output. The solution is of course to use parentheses:
(exists $hash{$_} and $hash{$_} eq 'on')
? ($result = 'OK')
: ($result = 'KO');
Nice gotcha you found there :)
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