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print $a+@b; #coerce array into number

This is exactly the same as array.length() in Java. It's not a type conversion.

print $a+$ref_b; #coerce reference into number

Those are both scalars. Not a type conversion.

my $d=eval %c; #coerce hash into string

This one is tricky. What the eval actually gets is certain internal information concerning the hash, which happens to be output as a valid perl expression (a division operation). You've lost all real information about the hash, and therefore is not a type conversion.

my @e=%c;print "@e"; #hashes and arrays are different types. Oh wait

My own view on this is that hashes and arrays are both subtypes of lists. So it's not so much a conversion between different types than between different subtypes. There are those that disagree, though.

my @t=12; #coerce number into array

This simply makes a scalar containing 12 that is placed as the first element of the list, and the list is then assigned to an array. The scalar is still there, so it's not a type conversion.

I think I've established a pattern here. None of these are really type conversions.

"There is no shame in being self-taught, only in not trying to learn in the first place." -- Atrus, Myst: The Book of D'ni.


In reply to Re: strong typing by hardburn
in thread (Completely OT) - Hero(i)n programming language on Slashdot by dragonchild

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