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Perl: the Markov chain saw

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( #3333=superdoc: print w/replies, xml ) Need Help??
Well, this does seem curious:
$ perl -v This is perl, v5.6.1 built for i586-linux ... $ perl -e '$u=""; print $u,$/; $u=~s/(.*?)\?(.*?)/$1/gs; print $u,$/;'
But you said that you only wanted the first part (before the "?"), so why did you put parens around the second part? It does work as desired this way:
$ perl -e '$u=""; print $u,$/; $u=~s/(.*?)\?.*/$1/; print $u,$/;'
For that matter, whether or not you use the following part as well, why not split:
$ perl -e '$u=""; print $u,$/; ($ub,$ue)=split(/\?/,$u,2); print "$ub :: $ue",$/;' :: a=b&c=d
Still, the initial example is baffling, and I hope someone can explain why it should behave the way it did, just for our communal peace of mind. The final "gs" is of course superfluous for this example -- the behavior is the same with or without those qualifiers on the regex. (And "extra strength" is not really an appropriate reason for using them, anyway; check their descriptions in perlre to see what their proper, intended functions are.)

In reply to Re: Regex Bug? by graff
in thread Regex Bug? by mt2k

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