> I guess my question is: why do you think I am throwing
> away a result which you only accomplish differently?
> "++" vs. "+ 1" -- they both add one to the value
> of $flip.
Um, no, they do not. Saying
$flip + 1;
does not change in any way the scalar referred to
by $flip, while "++$flip" does. Simple as that.
===
What, fundamentally, is the difference between
$flip = ++$flip % 4
and
$flip = ($flip + 1) % 4
===
The first changes the value of $flip twice, the
second, only once. In the first one, the computer
is saying:
- Increase the value of $flip by one
- Modulo 4 it
- Assign the result into $flip
versus:
- Compute the value of $flip + 1
- Modulo for that (temporary) value
- Assign the result into $flip
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