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( #3333=superdoc: print w/replies, xml ) Need Help??

A one-liner with PDL's rvals:

pdl> p rvals(19,19,{Centre=>[5,4]}) <= 6 [ [0 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0] [0 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0] [0 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] ]

Edit: I know what you are thinking: what a dumb one-liner. What if frame-buffer is 1000x1000 px, but illuminated area just 10x10? Why calculate a million distances when clearly we can limit calculations to a small viewport (bounding box)? Ok, then:

pdl> $frame = zeroes 19,19 pdl> ($x,$y,$r,$xmax,$ymax) = (5,4,6,dims $frame) pdl> pdl> use List::Util pdl> *min_ = \*List::Util::min pdl> *max_ = \*List::Util::max pdl> pdl> ($llx,$lly,$urx,$ury,$cx,$cy) = ( > max_(0,$x-$r), > max_(0,$y-$r), > min_($xmax,$x+$r), > min_($ymax,$y+$r), > min_($r,$x), > min_($r,$y)) pdl> pdl> $viewport = $frame($llx:$urx, $lly:$ury) pdl> pdl> $viewport .= $viewport-> rvals({ > Center => [$cx,$cy], > Squared => 1 > }) <= $r*$r pdl> pdl> p $frame [ [0 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0] [1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0] [0 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0] [0 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] ] pdl>

Note two different kinds of assignment, for data-flow to work in PDL. This nice exercise reminded me when taking a square root multiple times was a no-no (was that so for /[2-4]87/? I think nowadays it's single CPU cycle anyway, no need to optimize (-?)), hence I used the rvals's option (but it's there for a reason, isn't it). I hope I didn't mess anything this time of night and it works for border cases, too.


In reply to Re: circular area in a coordinates grid (AoA) (updated) by vr
in thread circular area in a coordinates grid (AoA) by Discipulus

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