Hi,
I am trying to construct a regex that extracts the string beween two quotes with the complication that that string may contain backslash-escaped quotes.
To illustrate:
my $rexeg = ???? # this is what I am after
my ($m1) = '"hubba bubba"' =~ $regex;
print "ok\n" if $m1 eq 'hubba bubba'; # should print "ok"
my ($m2) = '"hubba \"bubba\""' =~ $regex;
print "ok\n" if $m2 eq 'hubba "bubba"'; # should also print "ok"
I hope that is understandable...
I tried to do this with negative lookbehinds, but I attempt failed with "Variable length lookbehind not implemented", so am looking for some help here.
Many thanks!
-
Are you posting in the right place? Check out Where do I post X? to know for sure.
-
Posts may use any of the Perl Monks Approved HTML tags. Currently these include the following:
<code> <a> <b> <big>
<blockquote> <br /> <dd>
<dl> <dt> <em> <font>
<h1> <h2> <h3> <h4>
<h5> <h6> <hr /> <i>
<li> <nbsp> <ol> <p>
<small> <strike> <strong>
<sub> <sup> <table>
<td> <th> <tr> <tt>
<u> <ul>
-
Snippets of code should be wrapped in
<code> tags not
<pre> tags. In fact, <pre>
tags should generally be avoided. If they must
be used, extreme care should be
taken to ensure that their contents do not
have long lines (<70 chars), in order to prevent
horizontal scrolling (and possible janitor
intervention).
-
Want more info? How to link
or How to display code and escape characters
are good places to start.
|