if($ID = $ID2 and $mac2 = ''){
$$ref2{'Network ID 1'} = $mac;
}else{
push @extras,\$ref;
}
Are you aware that the expressions $ID = $ID2 and $mac2 = '' are assignments and not comparisons? In any case, the $mac2 = '' assignment will always be boolean false and the if-conditional will always be false. Probably what you meant was
if ($ID == $ID2 and $mac2 eq '') { ... } else { ... }
because $mac2 is certainly being compared to a string, and I suspect that $ID == $ID2 is likewise a string comparison and therefore should be $ID eq $ID2 instead.
Update: An example:
c:\@Work\Perl\monks>perl -wMstrict -le
"my ($ID, $ID2, $mac2) = ('foo', 'foo', '');
;;
if($ID eq $ID2 and $mac2 eq ''){
print 'true block';
}else{
print 'false block';
}
"
true block
c:\@Work\Perl\monks>perl -wMstrict -le
"my ($ID, $ID2, $mac2) = ('foo', 'foo', '');
;;
if($ID = $ID2 and $mac2 = ''){
print 'true block';
}else{
print 'false block';
}
"
false block
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