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Hi Monks,

I looking for a regular expression: I want to search for a sign(x), followed by a number n of any signs, followed by x, followed by the SAME number n of any signs, followed by x

the sign x of course is also allowed for the "any" signs

VAILD for example is :

xxx
x.x.x
x12x..x
x123x...x
x123x.x.x
[download]

NOT VALID for example (not the same number of signs between x)

x12x1x

A way would be to code every case. But this is not a smart way!

/(xxx)|(x..x..x)|(x...x...x)|(x.{4}x.{4}x)/

Follwoing is not working, because it would find the term x12x1x (not the same number of signs between x)

/x.{0,50}x.{0,50}x/

Many Thanks for any suggestion !

In reply to Regular Expression: search two times for the same number of any signs by Anonymous Monk

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