comment on

You could do something like this:

$s = 'a1 1 2 1.0 1.1 1.2 1.3';;
print grep defined, $s =~ m[([a-z]\d)\s+(\d)\s+(\d)(?:\s+(\d\.\d))?(?:
+\s+(\d\.\d))?(?:\s+(\d\.\d))?(?:\s+(\d\.\d))?(?:\s+(\d\.\d))?(?:\s+(\
+d\.\d))?(?:\s+(\d\.\d))?(?:\s+(\d\.\d))?];;
a1 1 2 1.0 1.1 1.2 1.3

$s = 'a1 1 2 1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7';;
print grep defined, $s =~ m[([a-z]\d)\s+(\d)\s+(\d)(?:\s+(\d\.\d))?(?:
+\s+(\d\.\d))?(?:\s+(\d\.\d))?(?:\s+(\d\.\d))?(?:\s+(\d\.\d))?(?:\s+(\
+d\.\d))?(?:\s+(\d\.\d))?(?:\s+(\d\.\d))?];;
a1 1 2 1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7
[download]

Not elegant, but it works.

You'd probably want to generate the regex:

$re = '([a-z]\d)\s+(\d)\s+(\d)' . join '', '(?:\s+(\d\.\d))?' x 10;;
$re = qr"$re";;

$s = 'a1 1 2 1.0 1.1 1.2 1.3';;
print grep defined, $s =~ $re;;
a1 1 2 1.0 1.1 1.2 1.3

$s = 'a1 1 2 1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7';;
print grep defined, $s =~ $re;;
a1 1 2 1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7
[download]

With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday'

Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.

"Science is about questioning the status quo. Questioning authority".

In the absence of evidence, opinion is indistinguishable from prejudice.

I'm with torvalds on this Agile (and TDD) debunked I told'em LLVM was the way to go. But did they listen!

In reply to Re: validate variable-length lines in one regex? by BrowserUk
in thread validate variable-length lines in one regex? by uhClem

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