Isn't an alias something dereferenced into a symbol table entry?
So a reference and an alias are on different levels of indirection.
DB<1> use Scalar::Util 'readonly'
DB<2> p readonly 1
134217728
DB<3> p readonly \1
0
DB<4> *one = \1
DB<5> p readonly $one
134217728
DB<6> $rone = \1
DB<7> p readonly $$rone
134217728
DB<8> $one = 2
Modification of a read-only value attempted at (eval 16)[/usr/share/pe
+rl/5.20/perl5db.pl:732] line 2.
DB<9> $$rone = 2
Modification of a read-only value attempted at (eval 17)[/usr/share/pe
+rl/5.20/perl5db.pl:732] line 2.
Greetings, -jo
$gryYup$d0ylprbpriprrYpkJl2xyl~rzg??P~5lp2hyl0p$
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