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> But $m is a reference
yes and no ... In proper CS speak it's a "call by reference", in Perl we tend to use "alias" for such passing. But in Perl speak it's not a "reference" like created by the reference operator \ see also https://perldoc.pl/perlglossary.html#call-by-reference
Cheers Rolf In reply to Re^2: Ternary Quizical behaviour?
by LanX
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