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( [id://3333]=superdoc: print w/replies, xml ) Need Help??
OK, vagabonding electron, sorry that I misunderstood your requirement, I thought the chains were the input. This a quick (probably not optimal) way to do it with your actual source data:
use strict; use warnings; use Data::Dumper; my %predec; while (<DATA>) { chomp; my ($succ, $pred) = split /;/, $_; $pred = $succ if $pred eq ''; push @{$predec{$pred}}, $succ; } my $continue = 1; while ($continue) { $continue = 0; for my $pred (keys %predec) { my $succ = @{$predec{$pred}}[-1]; if (defined $succ and exists $predec{$succ} and scalar @{$pred +ec{$succ}} != 0) { next if $succ eq $pred; push @{$predec{$pred}}, @{$predec{$succ}}; delete $predec{$succ}; $continue = 1; } $succ = @{$predec{$pred}}[0]; if (defined $succ and exists $predec{$succ} and scalar @{$pred +ec{$succ}} != 0) { unshift @{$predec{$pred}}, @{$predec{$succ}}; delete $predec{$succ}; $continue = 1; } } } print "Data structure: \n", Dumper \%predec; print "\n\nResult:\n\n"; for my $key (keys %predec) { next if scalar @{$predec{$key}} == 0; print "$key => $key\n" and next if $key eq @{$predec{$key}}[0]; print "$key => $key\n"; print "$_ => $key\n" for @{$predec{$key}}; } __DATA__ 567;456 456;345 345;234 234;123 339;228 228;117 131; 435;324 324;213 372;
This will print the following:
$ perl predecessor.pl Data structure: $VAR1 = { '123' => [ '234', '345', '456', '567' ], '131' => [ '131' ], '234' => [], '213' => [ '324', '435' ], '345' => [], '324' => [], '372' => [ '372' ], '117' => [ '228', '339' ] }; Result: 123 => 123 234 => 123 345 => 123 456 => 123 567 => 123 131 => 131 213 => 213 324 => 213 435 => 213 372 => 372 117 => 117 228 => 117 339 => 117
This seems to be what you want, except that the lines are not printed out in the same order as your example. If the order matters, it should be quite simple to sort the lines in the desired order.

In reply to Re^3: Looking for the first item in the chain by Laurent_R
in thread Looking for the first item in the chain by vagabonding electron

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