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( [id://3333]=superdoc: print w/replies, xml ) Need Help??
I think you only need one hash, and you just have to loop over it as often as necessary, to eliminate intermediate links in the chains:
use strict; use warnings; my %parent_of; <DATA>; # skip header while (<DATA>) { chomp; my ( $child, $parent ) = split( /;/ ); $parent ||= $child; $parent_of{$child} = $parent; $parent_of{$parent} = $parent unless ( exists( $parent_of{$parent} + )); } my $changes; do { $changes = 0; for my $child ( keys %parent_of ) { my $parent = $parent_of{$child}; while ( $parent_of{$parent} != $parent ) { my $next_parent = $parent_of{$parent}; $parent_of{$child} = $next_parent; $parent = $next_parent; $changes++; } } } while ( $changes ); for my $child ( sort keys %parent_of ) { print " $child => $parent_of{$child}\n"; } __DATA__ NUM;NUMPRED 567;456 456;345 345;234 234;123 339;228 228;117 131; 435;324 324;213 372; 789;678 678;567
(I commend you for using Text::CSV_XS, and you can certainly stick with that, but I assumed the input would be simple enough to do without it.) The DATA above includes some extra samples, to create a longer chain.

The point of the do {...} while ( $changes ) loop is simply to keep iterating over the "parent_of" hash, changing values for child keys until all the values represent "primary nodes" in all the chains.

Apart from that, I like the other suggestion given above: if possible, it would make more sense to create this form output as part of the same process that produces the sample input you've shown us here.


In reply to Re: Looking for the first item in the chain by graff
in thread Looking for the first item in the chain by vagabonding electron

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