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making a copy of the input string on each test iteration so as not to mess with the original.

Indeed, it is a pig to benchmark. Here's my attempt.

What I did was have the first iteration do tr[!][\n] and the second tr[\n][!], using a flag to keep track of odd & even. It also shows how the problem some people level at tr -- the need to know the lists at compile time -- can be addressed:

#! perl -slw use strict; use Benchmark qw[ cmpthese ]; sub makeTR{ eval "sub{ \$_[ 0 ] =~ tr[$_[0]][$_[1]] }"; } our $N //= 10; die "$N must be even and positive" if $N &1 or $N < 2; our $tr1 = makeTR( '!', "\n" ); our $tr2 = makeTR( "\n", '!' ); our $flag = 0; our $s = '1234!' x 55e3; cmpthese $N, { a => q[ if( $flag ) { my( $p, $c ) = ( 0, 50e3 ); 1 while --$c and $p = index $s, "\n", $p; $tr2->( substr $s, 0, $p ); $flag ^= 1; } else { my( $p, $c ) = ( 0, 50e3 ); 1 while --$c and $p = index $s, "!", $p; $tr1->( substr $s, 0, $p ); $flag ^= 1; } ], b => q[ if( $flag ) { $s =~ s/\n(??{ ( $myregexp::count++ < 50000 ) ? '' : '(?!) +' })/!/g; $flag ^= 1; } else { $s =~ s/!(??{ ( $myregexp::count++ < 50000 ) ? '' : '(?!)' + })/\n/g; $flag ^= 1; } ], };

And the results put tr 5x to 30x times faster, so your benchmark isn't bad at all:

C:\test>junk71 -N=2 (warning: too few iterations for a reliable count) (warning: too few iterations for a reliable count) s/iter a b a 5.84 -- -85% b 0.899 550% -- C:\test>junk71 -N=4 (warning: too few iterations for a reliable count) s/iter a b a 5.81 -- -92% b 0.492 1081% -- C:\test>junk71 -N=10 s/iter a b a 5.78 -- -95% b 0.273 2013% -- C:\test>junk71 -N=20 s/iter a b a 5.74 -- -97% b 0.176 3167% --

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In reply to Re^5: Fast Replacement (0.01 seconds) by BrowserUk
in thread Fast Replacement by sathishselvam

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