Building scalar from File::Find

sunadmn has asked for the wisdom of the Perl Monks concerning the following question:

Good day fellow monks I have the below code and have a it working for the most part but one issue I have ran into is when I build $out if there is not seven dirs I get output that looks like so:

net.somedomain......

Now the issue I would like to resolve is how can I build my $out scalar so that it will grab anything from dir 4 on and build itself from that,so if I have a file living under /net it will build $out like somedomain.net and if I have something like /us/pa/k12 it will look like somadomain.k12.pa.us and with either I wont have the trailing "." after the name if it doesn't equal seven in length. Any help you may all point out to me would be great as I am pulling my hair out trying to figure this one out right now.

Sunadmn
USE PERL

#!/usr/bin/perl

use strict;
use File::Find;
use FileHandle;

my $base    = "/chroot/named/master";
my $out     = "/var/tmp/current_list";



find(\&wanted, $base);

sub wanted {
   return unless ( -f "$File::Find::name" and $File::Find::name !~ m!/
+in-addr/! );

   my $name  = "$File::Find::name";
   my $zone  = new FileHandle "$name", "r";
   my $out   = join('.', ( split('/', $name) )[4..7]);
   print "$out\n";
}
[download]

Comment on Building scalar from File::Find Download Code

Replies are listed 'Best First'.
Re: Building scalar from File::Find by demerphq (Chancellor) on Dec 29, 2003 at 19:45 UTC
`my $out = join('.', ( split('/', $name) )[4..7]);` [download] Should be something like `my @dirs=split '/', $name ; my $out = join '.', @dirs[4..(@dirs<8 ? $#dirs : 7)];` [download] Also, your style probably encourages bad habits. You are quoting variables unnecessarily, and you are using indirect notation, both of which are not the best ideas. Good luck. --- demerphq _{First they ignore you, then they laugh at you, then they fight you, then you win. -- Gandhi}	[reply] [d/l] [select]
Re: Building scalar from File::Find by ysth (Canon) on Dec 30, 2003 at 03:37 UTC
From your description, maybe you want something like this: `#!/usr/bin/perl use strict; use warnings; use File::Find; my $base = "/home/sthoenna/bleadperl/perl"; find(\&wanted, $base); sub wanted { return unless ( -f "$File::Find::name" and $File::Find::name !~ m!/ +Encode/! ) ; my $name = "$File::Find::name"; my $out = join '.', grep defined, reverse( (split(m!/!, $name))[4 +..7] ); print "$out\n"; }` [download] Added warnings, reversing the names, removing unreached levels. Removed the extra my $out at the beginning; hope you realize that was a completely separate variable from the wanted sub's my $out. Removed the unused FileHandle stuff. I like to always say m// for the first parameter to split to remind me that it is a regex...it's too easy to do something like split '+' and be surprised when it fails. (The exception is " " (a single blank) which split treats specially, not as a regex.)	[reply] [d/l]


Clear questions and runnable code get the best and fastest answer
	PerlMonks