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Re: Reg expression on day

by flounder99 (Friar)
on Dec 23, 2003 at 17:59 UTC ( [id://316667]=note: print w/replies, xml ) Need Help??


in reply to Reg expression on day

If you only want to get rid of the leading zero on the day this would work:
s!/0?(\d+)/!/$1/!
If you want to get rid of the leading zeros on both the month and the day this would work:
s!0?(\d+)/0?(\d+)!$1/$2!
use strict; for ('12/09/2003', '12/10/2003', '01/01/2004') { my $date = $_; print "Before: $date\n"; $date =~ s!/0?(\d+)/!/$1/!; print "Leading zero off of day: $date\n"; $date = $_; $date =~ s!0?(\d+)/0?(\d+)!$1/$2!; print "Leading zero off of month and day: $date\n\n"; } __END__ Before: 12/09/2003 Leading zero off of day: 12/9/2003 Leading zero off of month and day: 12/9/2003 Before: 12/10/2003 Leading zero off of day: 12/10/2003 Leading zero off of month and day: 12/10/2003 Before: 01/01/2004 Leading zero off of day: 01/1/2004 Leading zero off of month and day: 1/1/2004

--

flounder

Replies are listed 'Best First'.
Re: Re: Reg expression on day
by boo_radley (Parson) on Dec 23, 2003 at 18:29 UTC
    you can replace
    $date =~ s!0?(\d+)/0?(\d+)!$1/$2!;
    with
    $date =~ s!0?(\d+/)!$1!g;
    for month and day.

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