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Re: Reg expression on day

by Paulster2 (Priest)
on Dec 23, 2003 at 17:55 UTC ( [id://316666]=note: print w/replies, xml ) Need Help??


in reply to Reg expression on day

An alternate way of doing this might be to break out your MM/DD/YYYY into seperate chunks (ie $MM = month, $DD = day, and $YYYY = year), then take the day variable and add zero to it. Then put it all back together again. This way you could manipulate the date if you needed to.

($MM, $DD, $YYYY) = split(/,"$date"); $MM=$MM+0; $DD=$DD+0; $date=$MM."/".$DD."/".$YYYY;

Please forgive me if my split syntax is incorrect. I don't have an example in front of me. Anyway, I am just providing an alternate methodry. Although if you absolutely need to use a regex or want to get better at using them, this definitely won't help you!

Have fun!

UPDATE: Thanks flounder99 for the correction, I thought that I was missing something!

Paulster2

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Re: Re: Reg expression on day
by flounder99 (Friar) on Dec 23, 2003 at 18:04 UTC
    Please forgive me if my split syntax is incorrect

    All you need is to quote your slash:

    split('/',"$date")
    I was thinking of something similar:
    s!(\d+)/(\d+)!($1+0).'/'.($2+0)!e

    --

    flounder

Re: Re: Reg expression on day
by trammell (Priest) on Dec 23, 2003 at 18:09 UTC
    Sure, and it cleans up a bit:

    $date = join "/", map $_+0, split m[/], $date;

    Not sure if I like the idea of stripping those zeroes though. Probably better to store the date in a saner format (Epoch seconds maybe?), then use POSIX::strftime() to generate the desired date format.

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