Please be sure to answer the question. ... but it was the Project Euler forums that showed me the formula to do it. Project Euler solutions Introduction. – Fabinout Jan 29 '14 at 16:24 Project Euler (projecteuler.net) is a series of challenging mathematical/computer programming problems that will require more than just mathematical insights to solve. I suppose that Euler_Project are for getting better at programming, I don't think you should handle answers as easily as you did. \$\begingroup\$ BTW it would be best to include the specification of the project Euler problem 1 in your question if you implemented the problem solution as stated in project euler. I solve Project Euler problems to practice and extend my math and programming skills, all while having fun at the same time. – Tangentially Perpendicular 15 mins ago The sum of these multiples is 23. Make an attempt, then come back with specific questions about any difficulties you're having. Problem 1: If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. Question 1: If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. If we list all the natural numbers below that are multiples of or , we get and . Project Euler #1: Multiples of 3 and 5. Since you have a generalized solution, you should provide your generalized specification of the problem. This problem is a programming version of Problem 1 from projecteuler.net. A more mathematical way to solve the first problem in the project Euler archives. Problem. The first challenge is the following. Find the sum of all the multiples of 3 or 5 below 1000. Solution Obvious solution. We won't just give you a solution - what would you learn if we did? Active today. May 3, 2011 Programming C++, Code, Project Euler Rian. If a box contains twenty-one coloured discs, composed of fifteen blue discs and six red discs, and two discs were taken at random, it can be seen that the probability of taking two blue discs, P(BB) = (15/21)×(14/20) = 1/2. Here I make my solutions publicly available for other enthusiasts to learn from and to critique. The series, 1 1 + 2 2 + 3 3 + … + 10 10 = 10405071317.. Find the last ten digits of the series, 1 1 + 2 2 + 3 3 + … + 1000 1000.. Project Euler Problem 1 Statement. The sum of these multiples is 23. If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. Problem 48 of Project Euler has the nice and simple description. C++ solution to Project Euler Problem 1. The sum of these multiples is 23. I'm learning C++ and currently doing Project Euler challenges. Ask Question Asked today. The sum of these multiples is 23. Project Euler is a teaching resource. Leaderboard. Submissions. Although mathematics will help you arrive at elegant and efficient methods, the use of a computer and … Especially when somebody already pointed out the problem in her code. … Discussions. Viewed 11 times 1 $\begingroup$ Okay so the problem itself is really simple, If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is . Jan 29 '14 at 16:24 Project Euler challenges this problem is a of... Solutions publicly available for other enthusiasts to learn from and to critique me... A generalized solution, you should provide your generalized specification of the problem fun at same. Euler forums that showed me the formula to do it you should handle answers as easily as you.. An attempt, then come back with specific questions about any difficulties 're. To solve more than just mathematical insights to solve to do it solutions! 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