Re: open failure code

What all these wise monks forgot to tell you is how they arrived at the answer :)

perl -MO=Deparse,-p
$down="false";
open (FH, $log) || $down = "true";
__END__
Can't modify logical or (||) in scalar assignment at - line 2, near ""
+true";"
- had compilation errors.
($down = 'false');
((open(FH, $log) || $down) = 'true');
[download]

B::Deparse

Comment on Re: open failure code Download Code

Replies are listed 'Best First'.
Re: Re: open failure code by Grygonos (Chaplain) on Nov 27, 2003 at 00:09 UTC
You could also use this type of contruct `open(FH,"<".$log) ? print "opened\n" : print "unable to open $!\n";` [download] it's not any better at all just making you aware of another option. Grygonos	[reply] [d/l]
Re: Re: Re: open failure code by jweed (Chaplain) on Nov 27, 2003 at 02:50 UTC
Though this works, the ternary operator, like the grep and map operators, should not really be use in void context. `if (open(FH,"<".$log) { print "opened\n"; } else { print "unable to open $!\n"; }` [download] is preferred. Who is Kayser Söze?	[reply] [d/l]
Re: Re: Re: Re: open failure code by davido (Cardinal) on Nov 27, 2003 at 05:47 UTC
Of course the same could be done just with proper logical short circuit operators. Prefer the low-precedence ones for this sort of thing: `open FH, "<", $log and print "Success\n" or print "Failure\n";` [download] That avoids trinaries and if/else's. Dave "If I had my life to live over again, I'd be a plumber." -- Albert Einstein	[reply] [d/l]


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