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Re: The N-queens problem using pure regexes

by thor (Priest)
on Oct 10, 2003 at 01:33 UTC ( [id://298153]=note: print w/replies, xml ) Need Help??


in reply to The N-queens problem using pure regexes

I think I've found a bug:
thor@bravo:~/perl> queens.pl -n 10 [a10 b8 c6 d9 e1 f1 g1 h7 i5 j2]
Wouldn't e1, f1, and g1 all be able to attack one another?

thor

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Re: The N-queens problem using pure regexes
by Abigail-II (Bishop) on Oct 10, 2003 at 08:24 UTC
    You are quite correct. The faulty solution can only happen with n >= 10; it happens because 'e10' isn't attacked by 'f1', and "e10" =~ /e1/. Luckely, the fix is simple:
    #!/usr/bin/perl use strict; use warnings 'all'; use Getopt::Long; Getopt::Long::Configure ("bundling"); GetOptions ('p|print' => \my $print, 'P|Print' => \my $Print, 'n|number=i' => \(my $nr_of_queens = 8) ); my @rows = 1 .. $nr_of_queens; my @cols = ('a' .. 'z') [0 .. $nr_of_queens - 1]; sub a2i {ord ($_ [0]) - ord ('a') + 1} sub i2a {chr ($_ [0] + ord ('a') - 1)} # Given a square, return all non-attacked squares on columns to # the *left* of the given square. (a1 is the lower left corner). sub free { my ($C, $R) = $_ [0] =~ /(\D)(\d+)/; $C = a2i $C; map {join "" => i2a ($_ -> [0]), $_ -> [1]} grep {$_ -> [0] != $C && $_ -> [1] != $R && abs ($_ -> [0] - $C) != abs ($_ -> [1] - $R)} map {my $c = a2i $_; map {[$c, $_]} @rows} @cols [0 .. $C - 1] } my ($str, $re) = ("", ""); foreach my $c (@cols) { $str .= ";," . (join "," => map {"$c$_"} @rows) . ",\n"; $re .= ";.*,(\\w+),.*\n"; next if $c eq 'a'; map {$str .= "$_:," . join (",," => free ($_)) . ",\n"} map {"$c$_ +"} @rows; my $C = a2i $c; $re .= "[^;]*\\$C:" . join ("" => map {".*,\\$_,"} 1 .. $C - 1) . +"[^;]*\n"; } if ($print || $Print) { print "'$str' =~ \n/^$re/\n"; exit if $Print; } if (my @a = $str =~ /^$re/) { print "[@a]\n"; } __END__

    Abigail

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