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### Re: ASCII Pattern - Golf (Russ: 83)

by Russ (Deacon)
 on Sep 19, 2003 at 02:39 UTC Need Help??

in reply to ASCII Pattern - Golf

I can get 83:
```\$i=9;do{print((map{(sort map{abs}\$_-\$ARGV[0],\$i-\$ARGV[1])[-1]}1..9),"\
+n")}while--\$i
[download]```

Russ

Replies are listed 'Best First'.
Re: Re: ASCII Pattern - Golf (Russ: 77)
by Russ (Deacon) on Sep 19, 2003 at 02:57 UTC
Okay, now 77 (if you don't miss the trailing newline):
```\$i=9;do{print"\n",map{(sort abs\$_-\$ARGV[0],abs\$i-\$ARGV[1])[-1]}1..9}wh
+ile--\$i
[download]```

Russ

74 :)
```\$i=9;do{print\$/,map{(sort abs\$_-\$ARGV[0],abs\$i-\$ARGV[1])[1]}1..9}while
+--\$i
[download]```

A for-loop is usually shorter than a do{...}while-loop. 70 :-)

\$t=abs\$ARGV[1]+\$_,print\$/,map{(sort\$t,abs\$ARGV[0]-\$_)[1]}1..9for-9..-1

If you want the newlines "right", I end up at 72:

\$t=abs\$ARGV[1]+\$_,print map((sort\$t,abs\$ARGV[0]-\$_)[1],1..9),\$/for-9..-1

Update: Well, what do you know ... the string \$ARGV[1]+\$_ is longer than the strings (\$s=pop) and \$s taken together. Make those 69 and 71 (both with tie-breaker at 30 different characters):

\$t=abs,print\$/,map+(sort\$t,abs\$ARGV[0]-\$_)[1],1..9for(\$s=pop)-9..\$s-1

... and ...

\$t=abs,print map((sort\$t,abs\$ARGV[0]-\$_)[1],1..9),\$/for(\$s=pop)-9..\$s-1

The Sidhekin
print "Just another Perl \${\(trickster and hacker)},"

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