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Re: Fisher-Yates theoryby Abigail-II (Bishop) |
| on Jul 24, 2003 at 13:16 UTC ( [id://277518]=note: print w/replies, xml ) | Need Help?? |
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I've no idea what you are trying to argue. I also don't
understand your table of situations. In the first move
of a Fisher-Yates shuffle, the last element is swapped,
so with an initial
after the first move we have one of:
Your table suggests a possible B, C, A after the first move, but you need at least two swaps to go from A, B, C to B, C, A. Abigail
In Section
Meditations
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