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Re: Rounding values upwards on an arbitrary basis

by Thelonius (Priest)
on Jul 02, 2003 at 20:56 UTC ( [id://270950]=note: print w/replies, xml ) Need Help??


in reply to Rounding values upwards on an arbitrary basis

I would do it with a binary search:
#!perl -w use strict; my %round; my @lowend; my $prevend = 0; # depends on input being sorted while (<DATA>) { if (/(\d+)\s*-\s*(\d+)\s*:\s*(\d+)/) { my ($start, $end, $target) = ($1, $2, $3); if ($start != $prevend + 1) { print STDERR "Warning: prevend=$prevend input=$_" } $prevend=$end; push @lowend, $start; $round{$start} = $target; } } sub customround { my ($val) = $_[0]; my $low = 0; my $high = $#lowend; # binary search while ($low < $high) { my $mid = int(($low + $high)/2); if ($lowend[$mid] < $val) { $low = $mid + 1; } elsif ($lowend[$mid] > $val) { $high = $mid - 1; } else { # found exact return $round{$lowend[$mid]}; } } $low++ unless $low == $#lowend; while ($low > 0 && $lowend[$low] > $val) { $low-- } return $round{$lowend[$low]}; } # test print "customround($_) = ", customround($_), "\n" for qw(0 1 5 6 7 10 14 15 16 19 20 99 100 124 125 126 1499 1500 1501) +; __DATA__ # Less than 10 1 - 5: 5 6 - 9: 10 # 10 to 100 10 - 14: 15 15 - 19: 20 20 - 24: 25 etc. # 100 to 1000 100 - 124: 125 125 - 149: 150 150 - 174: 175 etc. # 1000 and beyond 1000 - 1249: 1250 1250 - 1549: 1500 1500 - 1749: 1750 etc.

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