Re: Appending one array onto another

And here are my 2 Euro-Cent

@z=map{$_.$d[-1+push@d,shift@d]}@z;
[download]

Update: One can use a side-effect and avoid the assignment of an array:

map{$_.=$d[-1+push@d,shift@d]}@z;
[download]

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Re: Re: Appending one array onto another by sauoq (Abbot) on Jun 10, 2003 at 09:33 UTC
And using aliasing to our advantage but avoiding map in void context yields `$_ .= $d[-1 + push @d, shift @d] for @z;` [download] I'm not convinced that it's at all better than the first one in the OP though. This is a bit obscure for no really good reason. -sauoq "My two cents aren't worth a dime.";	[reply] [d/l]
Re: Re: Re: Appending one array onto another by Skeeve (Parson) on Jun 10, 2003 at 09:38 UTC
I like that one! It's obscure, yes. But not for "no really good reason" but for avoiding an aditional variable. But now as I think of it ;-) Okay: It's no really good reasone. Maybe I should think about my taking part in perl-minigolf and obfuscation.	[reply]