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Re: shift vs. @_ (where @_ evaluates to 1)by pfaut (Priest) |
on May 09, 2003 at 17:58 UTC ( [id://256952]=note: print w/replies, xml ) | Need Help?? |
my $strFoo = @_ evaluates @_ in scalar context. Arrays in scalar context return their size. What you want is my ($strFoo) = @_ which evaluates @_ in list context returning its values.
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