in reply to How is a perl program processed ?
When the bytecode is created the code is optimized, numbers will be calculated (like 1024*8 to 8192), quoted strings will be parsed, etc... And this is very important to can run nice and easy the code.
About the regex. Well, why parse and create for each regex? In the bytecode stage all the regex are parsed and created, and similar regex will use the same compiled regex. Note that regex is not a simple thing to do, and anything that can get speed is welcome!
I think that the best way to differ real compiled programs to interpreted, is the creation of binarys codes or not. A real binary code will have machine codes, that will be executed by the OS to work with the CPU instructions.
The definition of compilation can't tell you if is a interpreted program:
Compile: To put together, to construct, to build... To put together in a new form...
Just to remember some assembler. This code in C, when is compiled, is converted to Assembler fisrt:
The ADD is a CPU instruction (based on MIPS). But in the end everything is interpreted, if you think that CPU instructions are a language. ;-P## C: a = b + c + d ; ## Assembler: ADD a , b , c ADD a , a , d
About Perl supposed to be doing interpretation. Well, Perl don't follow any theorie/philosophy/concept just by the theorie/philosophy/concept. This is why the Perl interpreter is the faster and with the best memory management that exist.
The famous phrase:
"Perl is designed to make the easy jobs easy and the hard jobs possible."
-Larry Wall
Graciliano M. P.
"The creativity is the expression of the liberty".
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Re: Re: How is a perl program processed ?
by dakkar (Hermit) on Apr 01, 2003 at 08:11 UTC | |
by Abigail-II (Bishop) on Apr 01, 2003 at 09:17 UTC |