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### RE: \(\$a, \$b, \$c) eq (\\$a, \\$b, \\$c), is \\$a, \$b, \$c eq \\$a, \\$b, \\$c?

by autark (Friar)
 on Jul 23, 2000 at 04:19 UTC ( #23946=note: print w/replies, xml ) Need Help??

Let's have a look at the '\', '[]' and '()' constructs:
• [\$a, \$b, \$c] is a reference to an array with three scalar elements.
• \[\$a, \$b, \$c] is a reference to a scalar, which againg is a reference to an array with three scalar elements.
• [\\$a, \\$b, \\$c] is a reference to an array with three scalars. Each of theese three scalars is a reference to the real scalar.
So using the special braces '[' and ']' creates a reference to an array. If you use the normal braces '(' and ')' you group things into lists, so:
• (\$a, \$b, \$c) is a list of three scalar elements. It is not an array, but a list.
• \(\$a, \$b, \$c) is a list of three scalar elemnts. Each of theese three elements is a reference to the real scalar (that is your value "foo", "bar" and "baz")
• (\\$a, \\$b, \\$c) is excatly the same as \(\$a, \$b, \$c). The '\' operator will distribute over the list.
So if we use the [\$a, \$b, \$c] construct our list @list will contain one element, namely a reference to an array. If we on the other hand use the (\$a, \$b, \$c) construct, the list will contain 3 elements.

So then, an easier way to write [\\$a, \\$b, \\$c] would be [ \(\$a, \$b, \$c) ]. But still, this will not fix your example - I hope you can see the error in the example, but let's fix it:

```\$a = "foo";
\$b = "bar";
\$c = "baz";
@list = \(\$a, \$b, \$c);
foreach(@list) { print \$\$_ . "\n"; }
Autark.

Replies are listed 'Best First'.
RE: RE: \(\$a, \$b, \$c) eq (\\$a, \\$b, \\$c), is \\$a, \$b, \$c eq \\$a, \\$b, \\$c?
by Anonymous Monk on Jul 23, 2000 at 07:37 UTC
Thanks, I should RTFM some more. [\(\$a, \$b, \$c)] turns out to be what I was looking for.

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