Re: Question of variable interpolation in regex


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Re: Question of variable interpolation in regex

by tommyw (Hermit)

on Nov 15, 2002 at 16:51 UTC ( [id://213200]=note: print w/replies, xml )

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in reply to Question of variable interpolation in regex

This line $boxLine =~ s/\.+/$string/o; uses the /o modifier, so the regular expression is only compiled once. That is, even if the value of $string changes, the regular expression won't reflect that. So the first time through, it compiles as s/\.+/ 1/o and never changes again.

updated: Apparently, I'm talking rubbish. Sorry!

--
Tommy
Too stupid to live.
Too stubborn to die.

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Re: Re: Question of variable interpolation in regex by thelenm (Vicar) on Nov 15, 2002 at 16:56 UTC
Actually, the left-hand side of the substitution (the regex) is the part that is only compiled once. The right-hand side will change as `$string` changes. Try this: `my $foo = 'a'; for my $string ('b'..'z') { $foo =~ s/./$string/o; print "$foo\n"; }` [download] -- Mike `-- just,my${.02}`	[reply] [d/l] [select]

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