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Re: Little Perl Mysteries: what's your answer?

by robartes (Priest)
on Oct 30, 2002 at 22:21 UTC ( [id://209262]=note: print w/replies, xml ) Need Help??


in reply to Little Perl Mysteries: what's your answer?

And my 2 cents worth..
A function prototyped to accept no arguments is treated as a candidate for inlining by the Perl compiler. In this case sub foo(){2} will be inlined because it returns a constant. The snippet will thus print 2, because print foo(); is turned into print 2; by the compiler, no matter what you do to the definition of sub foo later on at runtime.
Nice one, Ovid!

CU
Robartes-

Replies are listed 'Best First'.
Re: Re: Little Perl Mysteries: what's your answer?
by dada (Chaplain) on Oct 31, 2002 at 08:54 UTC
    and the proof is: 
    c:\>perl -MO=Deparse -e "sub foo(){2};*::foo=sub(){3};print foo();"
sub foo () {
    2;
}
*foo = sub () {
    3;
}
;
print 2;
-e syntax OK

    [download]

    cheers,
    Aldo

    King of Laziness, Wizard of Impatience, Lord of Hubris

[reply]
[d/l]

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