Yes, but you can write your own version of map that takes a code reference as the first argument and an iterator as the second argument, thus solving your problem for Perl 5, rather than having to wait for Perl 6 to come out during Christmas :)

For more information on this, you can go to http://perl.plover.com/book/, subscribe to the mailing list and read the sample chapter. While I don't think that Dominus would mind my posting a brief code snippet to illustrate, I'm not entirely certain if that's appropriate, because he has asked that the chapter not be distributed (or even saved). As a result, I'm not entirely certain if it would be appropriate to post the code.

However, if you check it out, search for the &imap function. It seems to resolve what you're looking for. Again, I'd post it myself, but I'm not sure of what's appropriate there.

Update: I contacted Dominus via email to inquire about the appropriateness of this and he replied that his only reason for wanting to prevent distribution is to revise and correct the chapter so as to avoid error-filled drafts floating around the 'Net. Posting a snippet is therefore okay.

#!/usr/bin/perl -w
use strict;

sub NEXT { $_[0]->() }

sub imap (&$) {
    my ($transform, $it) = @_;
    return sub {
        my $next = NEXT($it);
        return unless defined $next;
        return $transform->($next);
    }
}

sub string_to_char_iter {
    my $string = shift;
    $string = reverse $string;
    sub { '' ne $string ? chop $string : undef }
}

my $string = join '', 'a' .. 'z';
my $iter = string_to_char_iter $string; 

my $uc_chars = imap { uc $_[0] } $iter;

while ( my $char = NEXT $uc_chars ) {
    print "$char\n";
}
[download]

For that code, we pass in a subref and an iterator (which is also a sub ref. We return yet another sub reference that will apply the first subref to the value returned from the iterator. In otherwords, we use the imap() function to transform one iterator into another, getting the results that you may need.

Cheers,
Ovid

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