The runtime scales with the product of the sizes of the two arrays.
So? ;-) No matter what method you choose, worst case, the runtime
will be at least proportional to the product of the sizes of the
two array, if only because that can be the output size. See below.
my %b_hash = map { $_ => 1 } @b_array;
my @new_array = grep $b_hash{$_}, @a_array;
You (and I think all of the others who answered this question)
just failed question 1b. This will only work if the elements
of
@b_array are unique - but that's not given, and
you shouldn't make that assumption; at least not without mentioning
it.
I'd do something like:
my %b_hash;
$b_hash {$_} ++ for @b_array;
my @c_array = map {($_) x ($b_hash {$_} || 0)} @a_array;
which has a running time of
O (sizeof (input) + sizeof (output)),
which is asymptotical optimal.
Abigail