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Remove from character to end of line

by sdyates (Scribe)
on Aug 01, 2002 at 16:39 UTC ( #186828=perlquestion: print w/replies, xml ) Need Help??

sdyates has asked for the wisdom of the Perl Monks concerning the following question:

This should be easy, but cannot quite do it.

here is the file:


here is what I want


herre is my logic:
- remove from first / to end of line
- remove / charcter.

I am using system command. I am not sure how to tell to remove from the first character to end of line.

sed 's/\/*//g' pslog3

I've done it before, but I do not have my perl reference book here!!

please help

Replies are listed 'Best First'.
Re: Remove from character to end of line
by $name (Pilgrim) on Aug 01, 2002 at 16:47 UTC
    You could do somthing like

    my $filename = "9077/00:00///:8087"; my @file = split('/', $filename); my $newname = $file[0];

    MGW Aplications Developer QuinnTeam Inc.
Re: Remove from character to end of line
by aufrank (Pilgrim) on Aug 01, 2002 at 16:57 UTC
    I would probably try a pattern like
    which matches at least one forward slash and then any characters after it. note that perlstyle recommends that you not use a forward slash as the delimiter for any substitution or match involving slashes, but I don't know if that works from the command line, so use whatever delimiter is most friendly with your shell. I'm sure some regex guru will be along soon to provide a better answer, but this gets the job done at least (I think).


Re: Remove from character to end of line
by particle (Vicar) on Aug 01, 2002 at 16:54 UTC
    my( $answer ) = ( $data =~ m!^(.+?)/!);

    ~Particle *accelerates*

Re: Remove from character to end of line
by CukiMnstr (Deacon) on Aug 01, 2002 at 16:50 UTC
    you have the s/// operator in perl. this should do what you want:
    while(<>) { s#^([^/]+).*#$1#; print; }

    hope this helps,

    Update: even if the s/// works, split() is faster:

    while(<>) { print((split '/')[0], "\n"); }

    Update: ++Abigail-II. I need to work on my golfing skills... ;)

      But that has to capture. You can do without capture:
      It's smaller code too. ;-)



        Not only smaller code, but smart code too. I knew there had to be an easy way. It is amazing how dumb I feel with out my reference books.

        Thanks much,
Re: Remove from character to end of line
by Tomte (Priest) on Aug 01, 2002 at 16:56 UTC
    my @lines = qw[ 9077/00:00///:8087 9079/00:00/////386/_]; my @erg; foreach (@lines){ s/([^\/]*)//; push @erg, $1; } # erg contains all segments you wanted


    update: damn, whenever I wrote and tested my examples, there are a bunch of so much cooler solutions....way to go tomte, way to go...:-)

    update_ii: s/$1 @erg/@erg, $1/

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