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Re^2: A better mod (%) operator?

by particle (Vicar)
on Jul 09, 2002 at 00:51 UTC ( #180364=note: print w/replies, xml ) Need Help??


in reply to (jeffa) Re: A better mod (%) operator?
in thread A better mod (%) operator?

The problem with overload though, is that you cannot define some new token such as /% - you have to use an existing one.
perl 6 solves this problem. something like:

my sub operator:%/ is prec(\&operator:%) ($x, $y) { ... }
i'll be glad i can finally add the ,= operator i've been looking for to replace push.

~Particle *accelerates*

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Re: Re^2: A better mod (%) operator?
by Kickstart (Pilgrim) on Jul 10, 2002 at 21:46 UTC
    Oooooooo....this is going to be SUCH a boon to the Perl Obfuscators :)

    Kickstart

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