Re: Re: Can't localize lexical variable $var at...

you wrote:
In particular, a sub outside the scope cannot see that variable.

But subs inside that scope are able to see that! And I cleanly see a way how that lexically scoped variable could be stacked, just like global variable!

But yes, I'll better just use lexical variables and implement stacking if I really need.

Best wishes,
Courage, the Cowardly Dog

Comment on Re: Re: Can't localize lexical variable $var at...

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Re^3: Can't localize lexical variable $var at... by Aristotle (Chancellor) on Jun 09, 2002 at 20:29 UTC
No, it cannot. If you `{ my $var; some_sub(); }`, then `some_sub()` cannot see `$var`. On the other hand, if you `{ local $var; some_sub(); }`, then `some_sub()` can. (And that's why you shouldn't `local` unless you have a clear reason for it and not before you have signed a contract that you clearly understand that perl is not liable if you botch up at that point, and that you accept the consequences.) Makeshifts last the longest.	[reply] [d/l] [select]
Re: Re^3: Can't localize lexical variable $var at... by Courage (Parson) on Jun 09, 2002 at 20:57 UTC
You did not understood what I meant. `{ my $var=2; sub inc {return $var++} sub dec {return $var--} } print inc; print dec;` [download] Those subs see that $var which is not seen outside that block, and perl doc says this is a trick to have private static variables. Courage, the Cowardly Dog.	[reply] [d/l]
Re^5: Can't localize lexical variable $var at... by Aristotle (Chancellor) on Jun 09, 2002 at 21:06 UTC
Now you are talking about closures. I do not see how that is relevant to localized globals? Makeshifts last the longest.	[reply]
Re^6: Can't localize lexical variable $var at... by Courage (Parson) on Jun 09, 2002 at 21:12 UTC


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