Oh no! You have inadvertantly tipped the scale of battle to favour the a opponent by the fact of its first attack and the effect which this has on the probability (random seed) for the retalitory attack of b - But what if the battle forces of b launch a preemptory attack?
Consider the following where Quantum::Entanglement has been used such that the victor is truly not known until the battle has been fought!
#!/usr/bin/perl
use Quantum::Entanglement;
my $opponent1 = entangle(1, 'a', 1, 'b');
my $opponent2 = p_op($opponent1, 'eq', 'a', sub{'b'}, sub{'a'});
$a = $b = 100;
$opponent1 = "$opponent1";
$opponent2 = "$opponent2";
{
no strict 'refs';
while ($$opponent1 > 0 && $$opponent2 > 0){
$$opponent1 -= rand($$opponent2 / 10);
$$opponent2 -= rand($$opponent1 / 10);
print qq($$opponent1 | $$opponent2\n)
}
print "And the winner is ... '",
(($$opponent1 < 0) ? $opponent1 : $opponent2),
"'\n";
}
Yes, I was bored :-)
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