update: true, but why would anyone  $foo = "$foo" if ref $foo?

 

______crazyinsomniac_____________________________ Of all the things I've lost, I miss my mind the most. perl -e "$q=$_;map({chr unpack qq;H*;,$_}split(q;;,q*H*));print;$q/$q;"

Stringification of references is irreversable.

Abigail

I don't understand your update. Is it a specific version if "why would anyone make a mistake"? I wouldn't know, but I'll keep warnings enabled and continue using strict anyway. Or do you mean why would they do:

    foo = "$foo" if ref $foo;
[download]

In that case, I don't see what that has to do with the thread.

Needless quoting of scalar is evil. You get into a habit where you easily make a mistake. Like quoting a ref. It might go well 99 times, but you are getting bitten the 100th time.

Abigail

I don't quite understand yours either ("is it a specific version if *question*?" what's that mean?).

Do you really consider my $email       = "$firstName" . "_" . "$lastName\@email.com"; quoting of a lone scalar?
( in my opinion, the '.' disqualifies it)

 


______crazyinsomniac_____________________________ Of all the things I've lost, I miss my mind the most. perl -e "$q=$_;map({chr unpack qq;H*;,$_}split(q;;,q*H*));print;$q/$q;"