http://qs321.pair.com?node_id=138008


in reply to while loops

Yours 

$num=20; 
$while($num<30){ 
   print "num is $num\n";
   $num=$num+1;\n ;
}

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should be

$num=20;<BR>
while($num<30){
   print "num is $num\n";
   $num+=$num;\n;
}

[download]

Replies are listed 'Best First'.
Re: Re: while loops
by rob_au (Abbot) on Jan 11, 2002 at 18:41 UTC
    No, not at all - Your code will only pass through a single iteration of the loop as on the first pass, the value of $num is added to $num. The result is that $num equals 40 and the while loop is exited. I think you may have been meaning, ignoring formatting syntax errors ...

    $num = 20;
while ($num < 30) {
    print "num is $num\n";
    ++$num;
}

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    Although, good pick up on the syntax error with the line - $while($num<30){ - Although this had been addressed previously within this thread.

     

    perl -e 's&&rob@cowsnet.com.au&&&split/[@.]/&&s&.com.&_&&&print'

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[select]
      yes , thanks

      in this case would $num++ also work

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Re^2: while loops
by lvanhout (Curate) on Jun 15, 2004 at 17:42 UTC
    Still not there. 

    $num=20; 
while($num<30) 
{ 
   print "num is $num\n";
   <b><u>$num+=$num;\n</b></u>
}

#I think you ment:
   $num += 1;

#Though these should work also:
   $num++;
   ++$num;

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    There is also an extra "\n;" in the code in the reply.
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