Re: while loops

Yours

$num=20; 
$while($num<30){ 
   print "num is $num\n";
   $num=$num+1;\n ;
}
[download]

should be

$num=20;<BR>
while($num<30){
   print "num is $num\n";
   $num+=$num;\n;
}
[download]

Comment on Re: while loops Select or Download Code

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Re: Re: while loops by rob_au (Abbot) on Jan 11, 2002 at 18:41 UTC
No, not at all - Your code will only pass through a single iteration of the loop as on the first pass, the value of `$num` is added to `$num`. The result is that `$num` equals `40` and the `while` loop is exited. I think you may have been meaning, ignoring formatting syntax errors ... `$num = 20; while ($num < 30) { print "num is $num\n"; ++$num; }` [download] Although, good pick up on the syntax error with the line - `$while($num<30){` - Although this had been addressed previously within this thread. `perl -e 's&&rob@cowsnet.com.au&&&split/[@.]/&&s&.com.&_&&&print'`	[reply] [d/l] [select]
Re: Re: Re: while loops by Glyndwr (Initiate) on Jan 11, 2002 at 19:11 UTC
yes , thanks in this case would $num++ also work	[reply]
Re^2: while loops by lvanhout (Curate) on Jun 15, 2004 at 17:42 UTC
Still not there. `$num=20; while($num<30) { print "num is $num\n"; <b><u>$num+=$num;\n</b></u> } #I think you ment: $num += 1; #Though these should work also: $num++; ++$num;` [download] There is also an extra "\n;" in the code in the reply.	[reply] [d/l]