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Re: substituting 1 escaped character for another

by pryrt (Abbot)
on Jul 26, 2018 at 16:59 UTC ( [id://1219327]=note: print w/replies, xml ) Need Help??


in reply to substituting 1 escaped character for another

that works for me. could you show us how it doesn't work for you (SSCCE):

__LINUX__
sh-3.00$ perl -le 'print $x = "healthy(b"; $x =~ s/\(/\</; print $x'
healthy(b
healthy<b
sh-3.00$ perl -v

This is perl, v5.8.5 built for i386-linux-thread-multi
...
__WINDOWS__
C:\>perl -le "print $x = 'healthy(b'; $x =~ s/\(/\</; print $x"
healthy(b
healthy<b

C:\>perl -v

This is perl 5, version 26, subversion 2 (v5.26.2) built for MSWin32-x
+64-multi-thread
...

[download]

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Re^2: substituting 1 escaped character for another
by choroba (Cardinal) on Jul 26, 2018 at 17:49 UTC
    Also note that the backslash in the replacement part is useless and could be even misleading as someone might think that \< has a special meaning. 
    s/\(/</

    [download]

    If there are more parentheses to replace, use the /g modifier: 

    s/\(/</g

    [download]

    Also, in case of single character replacements, you can use transliteration: 

    tr/(/</

    [download]

    ($q=q:Sq=~/;[c](.)(.)/;chr(-||-|5+lengthSq)`"S|oS2"`map{chr |+ord
}map{substrSq`S_+|`|}3E|-|`7**2-3:)=~y+S|`+$1,++print+eval$q,q,a,

    [download]
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