Sorry, Let me make it bit clear. I use $sql=$comFieldsV.$fromV.$Where; $comFieldsV ..I select all the fields. $fromV - the table with data $Where - I pass the filters. one of the filter conditions is  if ($ftype) { $Where = $Where . "AND G.FEAT_TYPE = '$ftype' "; } When I use a value like..abc, I get the data. But when I use abc;234 it passes only abc

You did not make it even a little bit clear, because you did not answer the question posed. Who is "it"? I think it will help you solve this problem if you figure out where the string "abc;234" is losing its second half. Hint: add

print $Where . "\n";

immediately after you create the string.

Better still, look into using placeholders; they simplify things like quoting a great deal. Here's a simple example:

my $stmt = <<'GPO';
select id_num id
from   reference
where  first_name = ?
and    shoe_size = ?
GPO
my $name = 'Howard';
my $shoe = 9; 
my $results_ref = $dbhandle->selectrow_hashref($stmt, undef, $name, $s
+hoe);
print $results_ref->{id};
[download]

first_name is a string field, shoe_size is numeric, but the syntax for me is the same.

But God demonstrates His own love toward us, in that while we were yet sinners, Christ died for us. Romans 5:8 (NASB)

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